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2x^2-31x-168=0
a = 2; b = -31; c = -168;
Δ = b2-4ac
Δ = -312-4·2·(-168)
Δ = 2305
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-\sqrt{2305}}{2*2}=\frac{31-\sqrt{2305}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+\sqrt{2305}}{2*2}=\frac{31+\sqrt{2305}}{4} $
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